The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies $E_1$ (lower) and $E_2$ (higher) is given by
- A$v = \frac{E_1+E_2}{h}$
- B$v = \frac{E_1 - E_2}{h}$
- C$v = \frac{E_1 \times E_2}{h}$
- D$v = \frac{E_2 - E_1}{h}$
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View SolutionAccording to Bohr's theory,
$E_{n} = \text{Total energy}, K_{n} = \text{Kinetic energy}, V_{n} = \text{Potential energy}, r_{n} = \text{Radius of } n^{\text{th}} \text{ orbit}$
Match the following:
Column $I$ Column $II$ $A$. $V_{n} / K_{n} = ?$ $P$. $0$ $B$. If radius of $n^{\text{th}}$ orbit $\propto E_{n}^{x}, x = ?$ $Q$. $-1$ $C$. Angular momentum in lowest orbital $R$. $-2$ $D$. $1/r_{n} \propto Z^{y}, y = ?$ $S$. $1$
$E_{n} = \text{Total energy}, K_{n} = \text{Kinetic energy}, V_{n} = \text{Potential energy}, r_{n} = \text{Radius of } n^{\text{th}} \text{ orbit}$
Match the following:
| Column $I$ | Column $II$ |
| $A$. $V_{n} / K_{n} = ?$ | $P$. $0$ |
| $B$. If radius of $n^{\text{th}}$ orbit $\propto E_{n}^{x}, x = ?$ | $Q$. $-1$ |
| $C$. Angular momentum in lowest orbital | $R$. $-2$ |
| $D$. $1/r_{n} \propto Z^{y}, y = ?$ | $S$. $1$ |
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